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112121300203 = 1110192845473
BaseRepresentation
bin110100001101011110…
…0110100010011101011
3101201101221000012012021
41220122330310103223
53314111023101303
6123301404325311
711046320220103
oct1503274642353
9351357005167
10112121300203
1143606607380
1219891243837
13a75ab34c23
1455d8c16203
152db346aebd
hex1a1af344eb

112121300203 has 4 divisors (see below), whose sum is σ = 122314145688. Its totient is φ = 101928454720.

The previous prime is 112121300189. The next prime is 112121300209. The reversal of 112121300203 is 302003121211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112121300203 - 213 = 112121292011 is a prime.

It is a super-2 number, since 2×1121213002032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112121300209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5096422726 + ... + 5096422747.

It is an arithmetic number, because the mean of its divisors is an integer number (30578536422).

Almost surely, 2112121300203 is an apocalyptic number.

112121300203 is a deficient number, since it is larger than the sum of its proper divisors (10192845485).

112121300203 is a wasteful number, since it uses less digits than its factorization.

112121300203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10192845484.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 112121300203 its reverse (302003121211), we get a palindrome (414124421414).

The spelling of 112121300203 in words is "one hundred twelve billion, one hundred twenty-one million, three hundred thousand, two hundred three".

Divisors: 1 11 10192845473 112121300203