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11212143233099 = 12650538862983
BaseRepresentation
bin1010001100101000011111…
…0100001000100001001011
31110200212111112120112000212
42203022013310020201023
52432144432131424344
635502442033151335
72235023235001304
oct243120764104113
943625445515025
1011212143233099
113633052611946
121310ba40bb54b
136343ba477853
142aa9562bb7ab
151469c0c4379e
hexa3287d0884b

11212143233099 has 4 divisors (see below), whose sum is σ = 11212153361136. Its totient is φ = 11212133105064.

The previous prime is 11212143233069. The next prime is 11212143233101. The reversal of 11212143233099 is 99033234121211.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11212143233099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11212143233069) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3166439 + ... + 5696544.

It is an arithmetic number, because the mean of its divisors is an integer number (2803038340284).

Almost surely, 211212143233099 is an apocalyptic number.

11212143233099 is a deficient number, since it is larger than the sum of its proper divisors (10128037).

11212143233099 is an equidigital number, since it uses as much as digits as its factorization.

11212143233099 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10128036.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 11212143233099 in words is "eleven trillion, two hundred twelve billion, one hundred forty-three million, two hundred thirty-three thousand, ninety-nine".

Divisors: 1 1265053 8862983 11212143233099