Base | Representation |
---|---|
bin | 10100111000100101… |
… | …11110011001000001 |
3 | 1001221101122110102000 |
4 | 22130102332121001 |
5 | 140430302420213 |
6 | 5052323214213 |
7 | 544563511614 |
oct | 123422763101 |
9 | 31841573360 |
10 | 11212154433 |
11 | 4833a72637 |
12 | 220ab17369 |
13 | 1098b7900c |
14 | 78513817b |
15 | 4594e9c73 |
hex | 29c4be641 |
11212154433 has 16 divisors (see below), whose sum is σ = 16658208000. Its totient is φ = 7453345680.
The previous prime is 11212154423. The next prime is 11212154453. The reversal of 11212154433 is 33445121211.
11212154433 is a `hidden beast` number, since 1 + 1 + 2 + 1 + 215 + 443 + 3 = 666.
It is a de Polignac number, because none of the positive numbers 2k-11212154433 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11212154397 and 11212154406.
It is not an unprimeable number, because it can be changed into a prime (11212154423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 585513 + ... + 604358.
It is an arithmetic number, because the mean of its divisors is an integer number (1041138000).
Almost surely, 211212154433 is an apocalyptic number.
It is an amenable number.
11212154433 is a deficient number, since it is larger than the sum of its proper divisors (5446053567).
11212154433 is a wasteful number, since it uses less digits than its factorization.
11212154433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1190229 (or 1190223 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
Adding to 11212154433 its reverse (33445121211), we get a palindrome (44657275644).
The spelling of 11212154433 in words is "eleven billion, two hundred twelve million, one hundred fifty-four thousand, four hundred thirty-three".
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