Base | Representation |
---|---|
bin | 10000010100001111010… |
… | …111010110011001100011 |
3 | 10222012010102212011021010 |
4 | 100110033113112121203 |
5 | 121332302011243210 |
6 | 2215031551232003 |
7 | 144002322550452 |
oct | 20241727263143 |
9 | 3865112764233 |
10 | 1121244243555 |
11 | 3a2576165677 |
12 | 16137a518603 |
13 | 8196b1985a7 |
14 | 3c3a8b18b99 |
15 | 1e275a96920 |
hex | 1050f5d6663 |
1121244243555 has 16 divisors (see below), whose sum is σ = 1794040139520. Its totient is φ = 597980479968.
The previous prime is 1121244243533. The next prime is 1121244243577. The reversal of 1121244243555 is 5553424421211.
It is an interprime number because it is at equal distance from previous prime (1121244243533) and next prime (1121244243577).
It is not a de Polignac number, because 1121244243555 - 28 = 1121244243299 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 454327 + ... + 1564896.
It is an arithmetic number, because the mean of its divisors is an integer number (112127508720).
Almost surely, 21121244243555 is an apocalyptic number.
1121244243555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1121244243555 is a deficient number, since it is larger than the sum of its proper divisors (672795895965).
1121244243555 is a wasteful number, since it uses less digits than its factorization.
1121244243555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2056250.
The product of its digits is 192000, while the sum is 39.
Adding to 1121244243555 its reverse (5553424421211), we get a palindrome (6674668664766).
The spelling of 1121244243555 in words is "one trillion, one hundred twenty-one billion, two hundred forty-four million, two hundred forty-three thousand, five hundred fifty-five".
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