1121300113 has 4 divisors (see below), whose sum is σ = 1131587380. Its totient is φ = 1111012848.

The previous prime is 1121300107. The next prime is 1121300129. The reversal of 1121300113 is 3110031211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 577104529 + 544195584 = 24023^2 + 23328^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121300113 - 2¹³ = 1121291921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1121300093 and 1121300102.

It is not an unprimeable number, because it can be changed into a prime (1121300183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5143470 + ... + 5143687.

It is an arithmetic number, because the mean of its divisors is an integer number (282896845).

Almost surely, 2^1121300113 is an apocalyptic number.

It is an amenable number.

1121300113 is a deficient number, since it is larger than the sum of its proper divisors (10287267).

1121300113 is a wasteful number, since it uses less digits than its factorization.

1121300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10287266.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1121300113 is about 33485.8195808315. The cubic root of 1121300113 is about 1038.9005000495.

Adding to 1121300113 its reverse (3110031211), we get a palindrome (4231331324).

The spelling of 1121300113 in words is "one billion, one hundred twenty-one million, three hundred thousand, one hundred thirteen".