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1121300342113 = 7943316981423
BaseRepresentation
bin10000010100010010101…
…101010110010101100001
310222012021100102021000111
4100110102231112111201
5121332410341421423
62215041313451321
7144003603435220
oct20242255262541
93865240367014
101121300342113
113a25a48a1316
12161395270b41
13819799aa7c3
143c3b235ccb7
151e27a97860d
hex10512b56561

1121300342113 has 8 divisors (see below), whose sum is σ = 1281622032128. Its totient is φ = 961012633824.

The previous prime is 1121300342111. The next prime is 1121300342119. The reversal of 1121300342113 is 3112430031211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1121300342113 - 21 = 1121300342111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1121300342111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8424681 + ... + 8556742.

It is an arithmetic number, because the mean of its divisors is an integer number (160202754016).

Almost surely, 21121300342113 is an apocalyptic number.

It is an amenable number.

1121300342113 is a deficient number, since it is larger than the sum of its proper divisors (160321690015).

1121300342113 is an equidigital number, since it uses as much as digits as its factorization.

1121300342113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16990863.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1121300342113 its reverse (3112430031211), we get a palindrome (4233730373324).

The spelling of 1121300342113 in words is "one trillion, one hundred twenty-one billion, three hundred million, three hundred forty-two thousand, one hundred thirteen".

Divisors: 1 7 9433 66031 16981423 118869961 160185763159 1121300342113