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11213301331 = 20149556519
BaseRepresentation
bin10100111000101110…
…10110011001010011
31001221110210201122201
422130113112121103
5140431101120311
65052403544031
7544606326421
oct123427263123
931843721581
1011213301331
114834686291
12220b38b017
13109918b05b
14785356111
154596749c1
hex29c5d6653

11213301331 has 4 divisors (see below), whose sum is σ = 11213878000. Its totient is φ = 11212724664.

The previous prime is 11213301311. The next prime is 11213301377. The reversal of 11213301331 is 13310331211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11213301331 - 213 = 11213293139 is a prime.

It is a super-2 number, since 2×112133013312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213301299 and 11213301308.

It is not an unprimeable number, because it can be changed into a prime (11213301301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258111 + ... + 298408.

It is an arithmetic number, because the mean of its divisors is an integer number (2803469500).

Almost surely, 211213301331 is an apocalyptic number.

11213301331 is a deficient number, since it is larger than the sum of its proper divisors (576669).

11213301331 is an equidigital number, since it uses as much as digits as its factorization.

11213301331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 576668.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11213301331 its reverse (13310331211), we get a palindrome (24523632542).

The spelling of 11213301331 in words is "eleven billion, two hundred thirteen million, three hundred one thousand, three hundred thirty-one".

Divisors: 1 20149 556519 11213301331