Base | Representation |
---|---|
bin | 10100111000101110… |
… | …11010111110111011 |
3 | 1001221110211200102201 |
4 | 22130113122332323 |
5 | 140431102220443 |
6 | 5052404211031 |
7 | 544606435255 |
oct | 123427327673 |
9 | 31843750381 |
10 | 11213320123 |
11 | 4834699415 |
12 | 220b399a77 |
13 | 1099196785 |
14 | 78535ccd5 |
15 | 45967a34d |
hex | 29c5dafbb |
11213320123 has 4 divisors (see below), whose sum is σ = 11214088240. Its totient is φ = 11212552008.
The previous prime is 11213320121. The next prime is 11213320189. The reversal of 11213320123 is 32102331211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32102331211 = 3823 ⋅8397157.
It is a cyclic number.
It is not a de Polignac number, because 11213320123 - 21 = 11213320121 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11213320123.
It is not an unprimeable number, because it can be changed into a prime (11213320121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 361728 + ... + 391501.
It is an arithmetic number, because the mean of its divisors is an integer number (2803522060).
Almost surely, 211213320123 is an apocalyptic number.
11213320123 is a deficient number, since it is larger than the sum of its proper divisors (768117).
11213320123 is an equidigital number, since it uses as much as digits as its factorization.
11213320123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768116.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11213320123 its reverse (32102331211), we get a palindrome (43315651334).
The spelling of 11213320123 in words is "eleven billion, two hundred thirteen million, three hundred twenty thousand, one hundred twenty-three".
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