Base | Representation |
---|---|
bin | 10100111000110111… |
… | …00110000010110011 |
3 | 1001221112220020221210 |
4 | 22130123212002303 |
5 | 140431342222003 |
6 | 5052443451203 |
7 | 544621642362 |
oct | 123433460263 |
9 | 31845806853 |
10 | 11214414003 |
11 | 4835276251 |
12 | 220b826b03 |
13 | 109948a640 |
14 | 7855657d9 |
15 | 4597e4503 |
hex | 29c6e60b3 |
11214414003 has 16 divisors (see below), whose sum is σ = 16329551616. Its totient is φ = 6803976480.
The previous prime is 11214413993. The next prime is 11214414019. The reversal of 11214414003 is 30041441211.
11214414003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11214414003 - 214 = 11214397619 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11214412003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2022225 + ... + 2027762.
It is an arithmetic number, because the mean of its divisors is an integer number (1020596976).
Almost surely, 211214414003 is an apocalyptic number.
11214414003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11214414003 is a deficient number, since it is larger than the sum of its proper divisors (5115137613).
11214414003 is a wasteful number, since it uses less digits than its factorization.
11214414003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4050074.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 11214414003 its reverse (30041441211), we get a palindrome (41255855214).
The spelling of 11214414003 in words is "eleven billion, two hundred fourteen million, four hundred fourteen thousand, three".
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