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11220020313 = 33740006771
BaseRepresentation
bin10100111001100001…
…11110110001011001
31001221221110002100220
422130300332301121
5140434311122223
65053203550253
7545020412325
oct123460766131
931857402326
1011220020313
114838455367
12221168b389
13109a6a1398
147861c4985
1545a0506e3
hex29cc3ec59

11220020313 has 4 divisors (see below), whose sum is σ = 14960027088. Its totient is φ = 7480013540.

The previous prime is 11220020311. The next prime is 11220020327. The reversal of 11220020313 is 31302002211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11220020313 - 21 = 11220020311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11220020292 and 11220020301.

It is not an unprimeable number, because it can be changed into a prime (11220020311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1870003383 + ... + 1870003388.

It is an arithmetic number, because the mean of its divisors is an integer number (3740006772).

Almost surely, 211220020313 is an apocalyptic number.

It is an amenable number.

11220020313 is a deficient number, since it is larger than the sum of its proper divisors (3740006775).

11220020313 is an equidigital number, since it uses as much as digits as its factorization.

11220020313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3740006774.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11220020313 its reverse (31302002211), we get a palindrome (42522022524).

The spelling of 11220020313 in words is "eleven billion, two hundred twenty million, twenty thousand, three hundred thirteen".

Divisors: 1 3 3740006771 11220020313