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1122014100131 = 7331530715007
BaseRepresentation
bin10000010100111101010…
…000000111101010100011
310222021010002110220221122
4100110331100013222203
5121340341102201011
62215240212042455
7144030361330331
oct20247520075243
93867102426848
101122014100131
113a2930788281
1216155430342b
1381a61826122
143c43d078b51
151e2bd4673db
hex1053d407aa3

1122014100131 has 4 divisors (see below), whose sum is σ = 1123544815872. Its totient is φ = 1120483384392.

The previous prime is 1122014100127. The next prime is 1122014100139. The reversal of 1122014100131 is 1310014102211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1122014100131 - 22 = 1122014100127 is a prime.

It is a super-3 number, since 3×11220141001313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1122014100139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 765356771 + ... + 765358236.

It is an arithmetic number, because the mean of its divisors is an integer number (280886203968).

Almost surely, 21122014100131 is an apocalyptic number.

1122014100131 is a deficient number, since it is larger than the sum of its proper divisors (1530715741).

1122014100131 is an equidigital number, since it uses as much as digits as its factorization.

1122014100131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1530715740.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1122014100131 its reverse (1310014102211), we get a palindrome (2432028202342).

The spelling of 1122014100131 in words is "one trillion, one hundred twenty-two billion, fourteen million, one hundred thousand, one hundred thirty-one".

Divisors: 1 733 1530715007 1122014100131