Base | Representation |
---|---|
bin | 10100111001101100… |
… | …10011000010010001 |
3 | 1001222001001220012011 |
4 | 22130312103002101 |
5 | 140440140222113 |
6 | 5053253502521 |
7 | 545035305544 |
oct | 123466230221 |
9 | 31861056164 |
10 | 11221414033 |
11 | 48392174a5 |
12 | 2212041a41 |
13 | 109aa6b87b |
14 | 78646885b |
15 | 45a22863d |
hex | 29cd93091 |
11221414033 has 4 divisors (see below), whose sum is σ = 11222709760. Its totient is φ = 11220118308.
The previous prime is 11221414021. The next prime is 11221414049. The reversal of 11221414033 is 33041412211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11221414033 - 221 = 11219316881 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11221413995 and 11221414013.
It is not an unprimeable number, because it can be changed into a prime (11221414013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 634785 + ... + 652222.
It is an arithmetic number, because the mean of its divisors is an integer number (2805677440).
Almost surely, 211221414033 is an apocalyptic number.
It is an amenable number.
11221414033 is a deficient number, since it is larger than the sum of its proper divisors (1295727).
11221414033 is an equidigital number, since it uses as much as digits as its factorization.
11221414033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1295726.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11221414033 its reverse (33041412211), we get a palindrome (44262826244).
The spelling of 11221414033 in words is "eleven billion, two hundred twenty-one million, four hundred fourteen thousand, thirty-three".
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