Base | Representation |
---|---|
bin | 11001100000111101111010… |
… | …011110101101011101000011 |
3 | 112201022210211100121001000111 |
4 | 121200331322132231131003 |
5 | 104202024212321212233 |
6 | 1034355342512332151 |
7 | 32431246402613053 |
oct | 3140757236553503 |
9 | 481283740531014 |
10 | 112216665413443 |
11 | 32834903163a38 |
12 | 10704412244057 |
13 | 4a7cca872a786 |
14 | 1d9d45bd77563 |
15 | ce902dc99acd |
hex | 660f7a7ad743 |
112216665413443 has 4 divisors (see below), whose sum is σ = 112237176598848. Its totient is φ = 112196154228040.
The previous prime is 112216665413353. The next prime is 112216665413471. The reversal of 112216665413443 is 344314566612211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112216665413443 is a prime.
It is a super-2 number, since 2×1122166654134432 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112216665413843) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10255584496 + ... + 10255595437.
It is an arithmetic number, because the mean of its divisors is an integer number (28059294149712).
Almost surely, 2112216665413443 is an apocalyptic number.
112216665413443 is a deficient number, since it is larger than the sum of its proper divisors (20511185405).
112216665413443 is an equidigital number, since it uses as much as digits as its factorization.
112216665413443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20511185404.
The product of its digits is 2488320, while the sum is 49.
The spelling of 112216665413443 in words is "one hundred twelve trillion, two hundred sixteen billion, six hundred sixty-five million, four hundred thirteen thousand, four hundred forty-three".
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