Base | Representation |
---|---|
bin | 110100010000101111… |
… | …1010010100101110001 |
3 | 101201200120102112121202 |
4 | 1220201133102211301 |
5 | 3314322114003213 |
6 | 123320323500545 |
7 | 11052121522616 |
oct | 1504137224561 |
9 | 351616375552 |
10 | 112231000433 |
11 | 43662523822 |
12 | 19901b27755 |
13 | a7777939c6 |
14 | 560961050d |
15 | 2dbcdd9b58 |
hex | 1a217d2971 |
112231000433 has 4 divisors (see below), whose sum is σ = 112232401008. Its totient is φ = 112229599860.
The previous prime is 112231000403. The next prime is 112231000457. The reversal of 112231000433 is 334000132211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 112231000433 - 214 = 112230984049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112231000403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 572291 + ... + 742952.
It is an arithmetic number, because the mean of its divisors is an integer number (28058100252).
Almost surely, 2112231000433 is an apocalyptic number.
It is an amenable number.
112231000433 is a deficient number, since it is larger than the sum of its proper divisors (1400575).
112231000433 is an equidigital number, since it uses as much as digits as its factorization.
112231000433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1400574.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 112231000433 its reverse (334000132211), we get a palindrome (446231132644).
The spelling of 112231000433 in words is "one hundred twelve billion, two hundred thirty-one million, four hundred thirty-three", and thus it is an aban number.
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