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11224132433 = 82321616311
BaseRepresentation
bin10100111010000001…
…01010101101010001
31001222020012000010122
422131000222231101
5140441334214213
65053432040025
7545100360113
oct123500525521
931866160118
1011224132433
11483a803908
122212b33015
13109b4b0ca7
147869753b3
1545a5b3d08
hex29d02ab51

11224132433 has 8 divisors (see below), whose sum is σ = 11244752256. Its totient is φ = 11203531200.

The previous prime is 11224132393. The next prime is 11224132501. The reversal of 11224132433 is 33423142211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11224132433 - 214 = 11224116049 is a prime.

It is a super-2 number, since 2×112241324332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11224032433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1775348 + ... + 1781658.

It is an arithmetic number, because the mean of its divisors is an integer number (1405594032).

Almost surely, 211224132433 is an apocalyptic number.

It is an amenable number.

11224132433 is a deficient number, since it is larger than the sum of its proper divisors (20619823).

11224132433 is an equidigital number, since it uses as much as digits as its factorization.

11224132433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9295.

The product of its digits is 3456, while the sum is 26.

Adding to 11224132433 its reverse (33423142211), we get a palindrome (44647274644).

The spelling of 11224132433 in words is "eleven billion, two hundred twenty-four million, one hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 823 2161 6311 1778503 5193953 13638071 11224132433