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112252213433 = 313621039143
BaseRepresentation
bin110100010001011000…
…0001101100010111001
3101201202001100021101102
41220202300031202321
53314343031312213
6123322402301145
711052500033243
oct1504260154271
9351661307342
10112252213433
11436734a2428
12199090577b5
13a77bcb0289
14560c373093
152dbebca158
hex1a22c0d8b9

112252213433 has 4 divisors (see below), whose sum is σ = 115873252608. Its totient is φ = 108631174260.

The previous prime is 112252213421. The next prime is 112252213531. The reversal of 112252213433 is 334312252211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112252213433 - 24 = 112252213417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112252213396 and 112252213405.

It is not an unprimeable number, because it can be changed into a prime (112252218433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1810519541 + ... + 1810519602.

It is an arithmetic number, because the mean of its divisors is an integer number (28968313152).

Almost surely, 2112252213433 is an apocalyptic number.

It is an amenable number.

112252213433 is a deficient number, since it is larger than the sum of its proper divisors (3621039175).

112252213433 is an equidigital number, since it uses as much as digits as its factorization.

112252213433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3621039174.

The product of its digits is 8640, while the sum is 29.

Adding to 112252213433 its reverse (334312252211), we get a palindrome (446564465644).

The spelling of 112252213433 in words is "one hundred twelve billion, two hundred fifty-two million, two hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 31 3621039143 112252213433