1123011300331 has 4 divisors (see below), whose sum is σ = 1123245803200. Its totient is φ = 1122776797464.

The previous prime is 1123011300319. The next prime is 1123011300353. The reversal of 1123011300331 is 1330031103211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123011300331 is a prime.

It is a super-2 number, since 2×1123011300331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1123011300299 and 1123011300308.

It is not an unprimeable number, because it can be changed into a prime (1123011300031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117244251 + ... + 117253828.

It is an arithmetic number, because the mean of its divisors is an integer number (280811450800).

Almost surely, 2^{1123011300331} is an apocalyptic number.

1123011300331 is a deficient number, since it is larger than the sum of its proper divisors (234502869).

1123011300331 is an equidigital number, since it uses as much as digits as its factorization.

1123011300331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234502868.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1123011300331 its reverse (1330031103211), we get a palindrome (2453042403542).

The spelling of 1123011300331 in words is "one trillion, one hundred twenty-three billion, eleven million, three hundred thousand, three hundred thirty-one".