Base | Representation |
---|---|
bin | 10000010101111011010… |
… | …001000100000110001011 |
3 | 10222100210121020111100022 |
4 | 100111323101010012023 |
5 | 121400003430110201 |
6 | 2215531340131055 |
7 | 144065224020311 |
oct | 20257321040613 |
9 | 3870717214308 |
10 | 1123054535051 |
11 | 3a3315009449 |
12 | 1617a4836a8b |
13 | 81b9924caa7 |
14 | 3c4db3100b1 |
15 | 1e32e98441b |
hex | 1057b44418b |
1123054535051 has 4 divisors (see below), whose sum is σ = 1123511249400. Its totient is φ = 1122597820704.
The previous prime is 1123054535047. The next prime is 1123054535093. The reversal of 1123054535051 is 1505354503211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1123054535051 - 22 = 1123054535047 is a prime.
It is a super-2 number, since 2×11230545350512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1123054535851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228353486 + ... + 228358403.
It is an arithmetic number, because the mean of its divisors is an integer number (280877812350).
Almost surely, 21123054535051 is an apocalyptic number.
1123054535051 is a deficient number, since it is larger than the sum of its proper divisors (456714349).
1123054535051 is an equidigital number, since it uses as much as digits as its factorization.
1123054535051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 456714348.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 1123054535051 in words is "one trillion, one hundred twenty-three billion, fifty-four million, five hundred thirty-five thousand, fifty-one".
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