Base | Representation |
---|---|
bin | 10000010101111110000… |
… | …011001100010000110011 |
3 | 10222100220212002211221201 |
4 | 100111332003030100303 |
5 | 121400102403331011 |
6 | 2215540125032031 |
7 | 144066331641466 |
oct | 20257603142063 |
9 | 3870825084851 |
10 | 1123101230131 |
11 | 3a3339402121 |
12 | 1617b83b5617 |
13 | 81ba5b1bb0a |
14 | 3c5035c72dd |
15 | 1e333b09cc1 |
hex | 1057e0cc433 |
1123101230131 has 4 divisors (see below), whose sum is σ = 1189166008392. Its totient is φ = 1057036451872.
The previous prime is 1123101230101. The next prime is 1123101230149. The reversal of 1123101230131 is 1310321013211.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1123101230131 - 25 = 1123101230099 is a prime.
It is a super-2 number, since 2×11231012301312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1123101230099 and 1123101230108.
It is not an unprimeable number, because it can be changed into a prime (1123101230101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33032389105 + ... + 33032389138.
It is an arithmetic number, because the mean of its divisors is an integer number (297291502098).
Almost surely, 21123101230131 is an apocalyptic number.
1123101230131 is a deficient number, since it is larger than the sum of its proper divisors (66064778261).
1123101230131 is an equidigital number, since it uses as much as digits as its factorization.
1123101230131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66064778260.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1123101230131 its reverse (1310321013211), we get a palindrome (2433422243342).
The spelling of 1123101230131 in words is "one trillion, one hundred twenty-three billion, one hundred one million, two hundred thirty thousand, one hundred thirty-one".
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