Search a number
-
+
112313110403 = 13191134023973
BaseRepresentation
bin110100010011001100…
…0100000111110000011
3101201220021221011022202
41220212120200332003
53320004124013103
6123332415423415
711054136454364
oct1504630407603
9351807834282
10112313110403
11436a49061aa
1219925524b6b
13a78b7b25a0
1456164a5b6b
152dc5208988
hex1a26620f83

112313110403 has 16 divisors (see below), whose sum is σ = 128445250080. Its totient is φ = 97347930624.

The previous prime is 112313110369. The next prime is 112313110417. The reversal of 112313110403 is 304011313211.

It is not a de Polignac number, because 112313110403 - 218 = 112312848259 is a prime.

It is a super-2 number, since 2×1123131104032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (112313110493) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1984076 + ... + 2039897.

It is an arithmetic number, because the mean of its divisors is an integer number (8027828130).

Almost surely, 2112313110403 is an apocalyptic number.

112313110403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

112313110403 is a deficient number, since it is larger than the sum of its proper divisors (16132139677).

112313110403 is a wasteful number, since it uses less digits than its factorization.

112313110403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4024118.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 112313110403 its reverse (304011313211), we get a palindrome (416324423614).

The spelling of 112313110403 in words is "one hundred twelve billion, three hundred thirteen million, one hundred ten thousand, four hundred three".

Divisors: 1 13 19 113 247 1469 2147 27911 4023973 52311649 76455487 454708949 993921331 5911216337 8639470031 112313110403