Base | Representation |
---|---|
bin | 110100010011001100… |
… | …0100000111110000011 |
3 | 101201220021221011022202 |
4 | 1220212120200332003 |
5 | 3320004124013103 |
6 | 123332415423415 |
7 | 11054136454364 |
oct | 1504630407603 |
9 | 351807834282 |
10 | 112313110403 |
11 | 436a49061aa |
12 | 19925524b6b |
13 | a78b7b25a0 |
14 | 56164a5b6b |
15 | 2dc5208988 |
hex | 1a26620f83 |
112313110403 has 16 divisors (see below), whose sum is σ = 128445250080. Its totient is φ = 97347930624.
The previous prime is 112313110369. The next prime is 112313110417. The reversal of 112313110403 is 304011313211.
It is not a de Polignac number, because 112313110403 - 218 = 112312848259 is a prime.
It is a super-2 number, since 2×1123131104032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (112313110493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1984076 + ... + 2039897.
It is an arithmetic number, because the mean of its divisors is an integer number (8027828130).
Almost surely, 2112313110403 is an apocalyptic number.
112313110403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
112313110403 is a deficient number, since it is larger than the sum of its proper divisors (16132139677).
112313110403 is a wasteful number, since it uses less digits than its factorization.
112313110403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4024118.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 112313110403 its reverse (304011313211), we get a palindrome (416324423614).
The spelling of 112313110403 in words is "one hundred twelve billion, three hundred thirteen million, one hundred ten thousand, four hundred three".
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