11232203000131 has 4 divisors (see below), whose sum is σ = 11236334008000. Its totient is φ = 11228071992264.

The previous prime is 11232203000101. The next prime is 11232203000171. The reversal of 11232203000131 is 13100030223211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11232203000131 - 2²⁹ = 11231666129219 is a prime.

It is a super-2 number, since 2×11232203000131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11232203000099 and 11232203000108.

It is not an unprimeable number, because it can be changed into a prime (11232203000101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2065499856 + ... + 2065505293.

It is an arithmetic number, because the mean of its divisors is an integer number (2809083502000).

Almost surely, 2^{11232203000131} is an apocalyptic number.

11232203000131 is a deficient number, since it is larger than the sum of its proper divisors (4131007869).

11232203000131 is an equidigital number, since it uses as much as digits as its factorization.

11232203000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4131007868.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11232203000131 its reverse (13100030223211), we get a palindrome (24332233223342).

The spelling of 11232203000131 in words is "eleven trillion, two hundred thirty-two billion, two hundred three million, one hundred thirty-one", and thus it is an aban number.