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11233011331 = 23488391797
BaseRepresentation
bin10100111011000101…
…00010011010000011
31001222211220002200201
422131202202122003
5141001122330311
65054350230031
7545236010113
oct123542423203
931884802621
1011233011331
114844818743
122215ab5317
1310a029c489
14787c07043
1545b2699c1
hex29d8a2683

11233011331 has 4 divisors (see below), whose sum is σ = 11721403152. Its totient is φ = 10744619512.

The previous prime is 11233011329. The next prime is 11233011373. The reversal of 11233011331 is 13311033211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11233011331 - 21 = 11233011329 is a prime.

It is a super-3 number, since 3×112330113313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11233011299 and 11233011308.

It is not an unprimeable number, because it can be changed into a prime (11233011311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244195876 + ... + 244195921.

It is an arithmetic number, because the mean of its divisors is an integer number (2930350788).

Almost surely, 211233011331 is an apocalyptic number.

11233011331 is a deficient number, since it is larger than the sum of its proper divisors (488391821).

11233011331 is an equidigital number, since it uses as much as digits as its factorization.

11233011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 488391820.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11233011331 its reverse (13311033211), we get a palindrome (24544044542).

The spelling of 11233011331 in words is "eleven billion, two hundred thirty-three million, eleven thousand, three hundred thirty-one".

Divisors: 1 23 488391797 11233011331