11234120410433 has 8 divisors (see below), whose sum is σ = 11315382805440. Its totient is φ = 11152864321200.

The previous prime is 11234120410421. The next prime is 11234120410463. The reversal of 11234120410433 is 33401402143211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11234120410433 - 2⁴ = 11234120410417 is a prime.

It is a super-2 number, since 2×11234120410433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11234120410396 and 11234120410405.

It is not an unprimeable number, because it can be changed into a prime (11234120410463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2029283 + ... + 5156183.

It is an arithmetic number, because the mean of its divisors is an integer number (1414422850680).

Almost surely, 2^{11234120410433} is an apocalyptic number.

It is an amenable number.

11234120410433 is a deficient number, since it is larger than the sum of its proper divisors (81262395007).

11234120410433 is a wasteful number, since it uses less digits than its factorization.

11234120410433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3152887.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11234120410433 its reverse (33401402143211), we get a palindrome (44635522553644).

The spelling of 11234120410433 in words is "eleven trillion, two hundred thirty-four billion, one hundred twenty million, four hundred ten thousand, four hundred thirty-three".