1123422655153 has 4 divisors (see below), whose sum is σ = 1127694224448. Its totient is φ = 1119151085860.

The previous prime is 1123422655139. The next prime is 1123422655177. The reversal of 1123422655153 is 3515562243211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1123422655153 - 2¹³ = 1123422646961 is a prime.

It is a super-2 number, since 2×1123422655153² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1123422655753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2135784253 + ... + 2135784778.

It is an arithmetic number, because the mean of its divisors is an integer number (281923556112).

Almost surely, 2^{1123422655153} is an apocalyptic number.

It is an amenable number.

1123422655153 is a deficient number, since it is larger than the sum of its proper divisors (4271569295).

1123422655153 is an equidigital number, since it uses as much as digits as its factorization.

1123422655153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4271569294.

The product of its digits is 216000, while the sum is 40.

Adding to 1123422655153 its reverse (3515562243211), we get a palindrome (4638984898364).

The spelling of 1123422655153 in words is "one trillion, one hundred twenty-three billion, four hundred twenty-two million, six hundred fifty-five thousand, one hundred fifty-three".