112344014221323 has 4 divisors (see below), whose sum is σ = 149792018961768. Its totient is φ = 74896009480880.

The previous prime is 112344014221253. The next prime is 112344014221337. The reversal of 112344014221323 is 323122410443211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112344014221323 - 2⁸ = 112344014221067 is a prime.

It is not an unprimeable number, because it can be changed into a prime (112344014221393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18724002370218 + ... + 18724002370223.

It is an arithmetic number, because the mean of its divisors is an integer number (37448004740442).

Almost surely, 2^{112344014221323} is an apocalyptic number.

112344014221323 is a deficient number, since it is larger than the sum of its proper divisors (37448004740445).

112344014221323 is an equidigital number, since it uses as much as digits as its factorization.

112344014221323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37448004740444.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 112344014221323 its reverse (323122410443211), we get a palindrome (435466424664534).

The spelling of 112344014221323 in words is "one hundred twelve trillion, three hundred forty-four billion, fourteen million, two hundred twenty-one thousand, three hundred twenty-three".