Search a number
-
+
112345052355 = 345277395191
BaseRepresentation
bin110100010100001001…
…0010111010011000011
3101201222112000222110000
41220220102113103003
53320040313133410
6123335520211043
711055005121534
oct1505022272303
9351875028400
10112345052355
1143710942708
1219934169a83
13a7952b7453
14561a81c68b
152dc7e17dc0
hex1a284974c3

112345052355 has 20 divisors (see below), whose sum is σ = 201388909392. Its totient is φ = 59917361040.

The previous prime is 112345052353. The next prime is 112345052371. The reversal of 112345052355 is 553250543211.

112345052355 is a `hidden beast` number, since 1 + 1 + 2 + 34 + 50 + 523 + 55 = 666.

It is not a de Polignac number, because 112345052355 - 21 = 112345052353 is a prime.

It is not an unprimeable number, because it can be changed into a prime (112345052353) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 138697191 + ... + 138698000.

Almost surely, 2112345052355 is an apocalyptic number.

112345052355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

112345052355 is a deficient number, since it is larger than the sum of its proper divisors (89043857037).

112345052355 is an equidigital number, since it uses as much as digits as its factorization.

112345052355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 277395208 (or 277395199 counting only the distinct ones).

The product of its (nonzero) digits is 90000, while the sum is 36.

Adding to 112345052355 its reverse (553250543211), we get a palindrome (665595595566).

The spelling of 112345052355 in words is "one hundred twelve billion, three hundred forty-five million, fifty-two thousand, three hundred fifty-five".

Divisors: 1 3 5 9 15 27 45 81 135 405 277395191 832185573 1386975955 2496556719 4160927865 7489670157 12482783595 22469010471 37448350785 112345052355