Base | Representation |
---|---|
bin | 110100010100001001… |
… | …0010111010011000011 |
3 | 101201222112000222110000 |
4 | 1220220102113103003 |
5 | 3320040313133410 |
6 | 123335520211043 |
7 | 11055005121534 |
oct | 1505022272303 |
9 | 351875028400 |
10 | 112345052355 |
11 | 43710942708 |
12 | 19934169a83 |
13 | a7952b7453 |
14 | 561a81c68b |
15 | 2dc7e17dc0 |
hex | 1a284974c3 |
112345052355 has 20 divisors (see below), whose sum is σ = 201388909392. Its totient is φ = 59917361040.
The previous prime is 112345052353. The next prime is 112345052371. The reversal of 112345052355 is 553250543211.
112345052355 is a `hidden beast` number, since 1 + 1 + 2 + 34 + 50 + 523 + 55 = 666.
It is not a de Polignac number, because 112345052355 - 21 = 112345052353 is a prime.
It is not an unprimeable number, because it can be changed into a prime (112345052353) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 138697191 + ... + 138698000.
Almost surely, 2112345052355 is an apocalyptic number.
112345052355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112345052355 is a deficient number, since it is larger than the sum of its proper divisors (89043857037).
112345052355 is an equidigital number, since it uses as much as digits as its factorization.
112345052355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277395208 (or 277395199 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 112345052355 its reverse (553250543211), we get a palindrome (665595595566).
The spelling of 112345052355 in words is "one hundred twelve billion, three hundred forty-five million, fifty-two thousand, three hundred fifty-five".
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