Base | Representation |
---|---|
bin | 10000010110010011111… |
… | …110110000111001110011 |
3 | 10222101212111110001011012 |
4 | 100112103332300321303 |
5 | 121401331101340433 |
6 | 2220040431141135 |
7 | 144111420236402 |
oct | 20262376607163 |
9 | 3871774401135 |
10 | 1123469168243 |
11 | 3a3508069504 |
12 | 16189b6747ab |
13 | 81c34115a86 |
14 | 3c53a403639 |
15 | 1e356088848 |
hex | 10593fb0e73 |
1123469168243 has 4 divisors (see below), whose sum is σ = 1123563029448. Its totient is φ = 1123375307040.
The previous prime is 1123469168197. The next prime is 1123469168267. The reversal of 1123469168243 is 3428619643211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1123469168243 - 224 = 1123452391027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1123469168191 and 1123469168200.
It is not an unprimeable number, because it can be changed into a prime (1123469162243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46912646 + ... + 46936587.
It is an arithmetic number, because the mean of its divisors is an integer number (280890757362).
Almost surely, 21123469168243 is an apocalyptic number.
1123469168243 is a deficient number, since it is larger than the sum of its proper divisors (93861205).
1123469168243 is an equidigital number, since it uses as much as digits as its factorization.
1123469168243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93861204.
The product of its digits is 1492992, while the sum is 50.
The spelling of 1123469168243 in words is "one trillion, one hundred twenty-three billion, four hundred sixty-nine million, one hundred sixty-eight thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •