Base | Representation |
---|---|
bin | 110100010100011010… |
… | …1010101110101111001 |
3 | 101202000011021211001111 |
4 | 1220220311111311321 |
5 | 3320100140041213 |
6 | 123340444520321 |
7 | 11055146060536 |
oct | 1505065256571 |
9 | 352004254044 |
10 | 112354221433 |
11 | 43716035563 |
12 | 199372500a1 |
13 | a797177a3c |
14 | 561bb27d8d |
15 | 2dc8b29a3d |
hex | 1a28d55d79 |
112354221433 has 16 divisors (see below), whose sum is σ = 121084346880. Its totient is φ = 103870771200.
The previous prime is 112354221391. The next prime is 112354221451. The reversal of 112354221433 is 334122453211.
It is a cyclic number.
It is not a de Polignac number, because 112354221433 - 233 = 103764286841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112354221395 and 112354221404.
It is not an unprimeable number, because it can be changed into a prime (112354321433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 155353 + ... + 498841.
It is an arithmetic number, because the mean of its divisors is an integer number (7567771680).
Almost surely, 2112354221433 is an apocalyptic number.
It is an amenable number.
112354221433 is a deficient number, since it is larger than the sum of its proper divisors (8730125447).
112354221433 is a wasteful number, since it uses less digits than its factorization.
112354221433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343848.
The product of its digits is 17280, while the sum is 31.
Adding to 112354221433 its reverse (334122453211), we get a palindrome (446476674644).
The spelling of 112354221433 in words is "one hundred twelve billion, three hundred fifty-four million, two hundred twenty-one thousand, four hundred thirty-three".
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