Base | Representation |
---|---|
bin | 110100010110010010… |
… | …1011100000010111011 |
3 | 101202011112201111110111 |
4 | 1220230211130002323 |
5 | 3320212243131103 |
6 | 123351013525151 |
7 | 11056542051151 |
oct | 1505445340273 |
9 | 352145644414 |
10 | 112417161403 |
11 | 43748614268 |
12 | 199543437b7 |
13 | a7a7213c21 |
14 | 562622d3d1 |
15 | 2dce40d86d |
hex | 1a2c95c0bb |
112417161403 has 4 divisors (see below), whose sum is σ = 114322537080. Its totient is φ = 110511785728.
The previous prime is 112417161379. The next prime is 112417161557. The reversal of 112417161403 is 304161714211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304161714211 = 23 ⋅13224422357.
It is a cyclic number.
It is not a de Polignac number, because 112417161403 - 217 = 112417030331 is a prime.
It is not an unprimeable number, because it can be changed into a prime (112417164403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 952687750 + ... + 952687867.
It is an arithmetic number, because the mean of its divisors is an integer number (28580634270).
Almost surely, 2112417161403 is an apocalyptic number.
112417161403 is a deficient number, since it is larger than the sum of its proper divisors (1905375677).
112417161403 is an equidigital number, since it uses as much as digits as its factorization.
112417161403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1905375676.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 112417161403 its reverse (304161714211), we get a palindrome (416578875614).
The spelling of 112417161403 in words is "one hundred twelve billion, four hundred seventeen million, one hundred sixty-one thousand, four hundred three".
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