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1124312040553 = 131512381240551
BaseRepresentation
bin10000010111000110001…
…110000100010001101001
310222111001020110101121011
4100113012032010101221
5121410042340244203
62220300220543521
7144141333443152
oct20270616042151
93874036411534
101124312040553
113a38aa921999
12161a959b1ba1
13820399299a0
143c5ba32c929
151e3a507d76d
hex105c6384469

1124312040553 has 16 divisors (see below), whose sum is σ = 1219333070592. Its totient is φ = 1030516200000.

The previous prime is 1124312040539. The next prime is 1124312040581. The reversal of 1124312040553 is 3550402134211.

It is a cyclic number.

It is not a de Polignac number, because 1124312040553 - 233 = 1115722105961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1124312040053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4553628 + ... + 4794178.

It is an arithmetic number, because the mean of its divisors is an integer number (76208316912).

Almost surely, 21124312040553 is an apocalyptic number.

1124312040553 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1124312040553 is a deficient number, since it is larger than the sum of its proper divisors (95021030039).

1124312040553 is a wasteful number, since it uses less digits than its factorization.

1124312040553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243096.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1124312040553 its reverse (3550402134211), we get a palindrome (4674714174764).

The spelling of 1124312040553 in words is "one trillion, one hundred twenty-four billion, three hundred twelve million, forty thousand, five hundred fifty-three".

Divisors: 1 13 151 1963 2381 30953 240551 359531 3127163 4673903 36323201 472201613 572751931 7445775103 86485541581 1124312040553