112433101113 has 4 divisors (see below), whose sum is σ = 149910801488. Its totient is φ = 74955400740.

The previous prime is 112433101097. The next prime is 112433101117. The reversal of 112433101113 is 311101334211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 112433101113 - 2⁴ = 112433101097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 112433101113.

It is not an unprimeable number, because it can be changed into a prime (112433101117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18738850183 + ... + 18738850188.

It is an arithmetic number, because the mean of its divisors is an integer number (37477700372).

Almost surely, 2^112433101113 is an apocalyptic number.

It is an amenable number.

112433101113 is a deficient number, since it is larger than the sum of its proper divisors (37477700375).

112433101113 is an equidigital number, since it uses as much as digits as its factorization.

112433101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37477700374.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 112433101113 its reverse (311101334211), we get a palindrome (423534435324).

The spelling of 112433101113 in words is "one hundred twelve billion, four hundred thirty-three million, one hundred one thousand, one hundred thirteen".