Base | Representation |
---|---|
bin | 110100010110110001… |
… | …0010000100010011011 |
3 | 101202012122201112000222 |
4 | 1220231202100202123 |
5 | 3320230333330201 |
6 | 123352343350255 |
7 | 11060124424121 |
oct | 1505542204233 |
9 | 352178645028 |
10 | 112433105051 |
11 | 43756613a33 |
12 | 1995975238b |
13 | a7aa606c37 |
14 | 56283bd911 |
15 | 2dd0a0c91b |
hex | 1a2d89089b |
112433105051 has 4 divisors (see below), whose sum is σ = 112616520192. Its totient is φ = 112249689912.
The previous prime is 112433105041. The next prime is 112433105069. The reversal of 112433105051 is 150501334211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112433105051 - 210 = 112433104027 is a prime.
It is a super-2 number, since 2×1124331050512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 112433105051.
It is not an unprimeable number, because it can be changed into a prime (112433105021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91706651 + ... + 91707876.
It is an arithmetic number, because the mean of its divisors is an integer number (28154130048).
Almost surely, 2112433105051 is an apocalyptic number.
112433105051 is a deficient number, since it is larger than the sum of its proper divisors (183415141).
112433105051 is an equidigital number, since it uses as much as digits as its factorization.
112433105051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183415140.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 112433105051 its reverse (150501334211), we get a palindrome (262934439262).
The spelling of 112433105051 in words is "one hundred twelve billion, four hundred thirty-three million, one hundred five thousand, fifty-one".
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