112433113 has 4 divisors (see below), whose sum is σ = 121081828. Its totient is φ = 103784400.

The previous prime is 112433107. The next prime is 112433117. The reversal of 112433113 is 311334211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4439449 + 107993664 = 2107^2 + 10392^2 .

It is a cyclic number.

It is not a de Polignac number, because 112433113 - 2⁵ = 112433081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112433117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4324338 + ... + 4324363.

It is an arithmetic number, because the mean of its divisors is an integer number (30270457).

Almost surely, 2^112433113 is an apocalyptic number.

112433113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

112433113 is a deficient number, since it is larger than the sum of its proper divisors (8648715).

112433113 is an equidigital number, since it uses as much as digits as its factorization.

112433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8648714.

The product of its digits is 216, while the sum is 19.

The square root of 112433113 is about 10603.4481655733. The cubic root of 112433113 is about 482.6490012048.

Adding to 112433113 its reverse (311334211), we get a palindrome (423767324).

The spelling of 112433113 in words is "one hundred twelve million, four hundred thirty-three thousand, one hundred thirteen".