Base | Representation |
---|---|
bin | 11001100100010001101011… |
… | …000100011110000100001001 |
3 | 112202010112201111021002000120 |
4 | 121210101223010132010021 |
5 | 104214240343234034423 |
6 | 1035052025014053453 |
7 | 32453546065125420 |
oct | 3144215304360411 |
9 | 482115644232016 |
10 | 112444040143113 |
11 | 32912282283768 |
12 | 107404a964a289 |
13 | 4a98573261833 |
14 | 1daa46b9642b7 |
15 | ceedda624ee3 |
hex | 66446b11e109 |
112444040143113 has 16 divisors (see below), whose sum is σ = 171343447367040. Its totient is φ = 64253681686656.
The previous prime is 112444040143021. The next prime is 112444040143151. The reversal of 112444040143113 is 311341040444211.
It is not a de Polignac number, because 112444040143113 - 29 = 112444040142601 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (112444040145113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46956973 + ... + 49293461.
It is an arithmetic number, because the mean of its divisors is an integer number (10708965460440).
Almost surely, 2112444040143113 is an apocalyptic number.
It is an amenable number.
112444040143113 is a deficient number, since it is larger than the sum of its proper divisors (58899407223927).
112444040143113 is a wasteful number, since it uses less digits than its factorization.
112444040143113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4628176.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 112444040143113 its reverse (311341040444211), we get a palindrome (423785080587324).
The spelling of 112444040143113 in words is "one hundred twelve trillion, four hundred forty-four billion, forty million, one hundred forty-three thousand, one hundred thirteen".
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