11252694345 has 16 divisors (see below), whose sum is σ = 18041909760. Its totient is φ = 5988904064.

The previous prime is 11252694331. The next prime is 11252694353. The reversal of 11252694345 is 54349625211.

It is a cyclic number.

It is not a de Polignac number, because 11252694345 - 2⁹ = 11252693833 is a prime.

It is a super-3 number, since 3×11252694345³ (a number of 31 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11252694297 and 11252694306.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 775884 + ... + 790253.

It is an arithmetic number, because the mean of its divisors is an integer number (1127619360).

Almost surely, 2^11252694345 is an apocalyptic number.

11252694345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11252694345 is a deficient number, since it is larger than the sum of its proper divisors (6789215415).

11252694345 is a wasteful number, since it uses less digits than its factorization.

11252694345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1566624.

The product of its digits is 259200, while the sum is 42.

The spelling of 11252694345 in words is "eleven billion, two hundred fifty-two million, six hundred ninety-four thousand, three hundred forty-five".