Base | Representation |
---|---|
bin | 10100111101011101… |
… | …10010011101100011 |
3 | 1002001020111122001002 |
4 | 22132232302131203 |
5 | 141021232000120 |
6 | 5100342502215 |
7 | 545600631164 |
oct | 123656623543 |
9 | 32036448032 |
10 | 11253000035 |
11 | 4855030532 |
12 | 222073496b |
13 | 10a447a704 |
14 | 78a72b76b |
15 | 45cdb7375 |
hex | 29ebb2763 |
11253000035 has 4 divisors (see below), whose sum is σ = 13503600048. Its totient is φ = 9002400024.
The previous prime is 11253000019. The next prime is 11253000037. The reversal of 11253000035 is 53000035211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11253000035 - 24 = 11253000019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11252999980 and 11253000016.
It is not an unprimeable number, because it can be changed into a prime (11253000037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125299999 + ... + 1125300008.
It is an arithmetic number, because the mean of its divisors is an integer number (3375900012).
Almost surely, 211253000035 is an apocalyptic number.
11253000035 is a deficient number, since it is larger than the sum of its proper divisors (2250600013).
11253000035 is an equidigital number, since it uses as much as digits as its factorization.
11253000035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2250600012.
The product of its (nonzero) digits is 450, while the sum is 20.
Adding to 11253000035 its reverse (53000035211), we get a palindrome (64253035246).
The spelling of 11253000035 in words is "eleven billion, two hundred fifty-three million, thirty-five", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.109 sec. • engine limits •