Base | Representation |
---|---|
bin | 10100111101100011… |
… | …00001000000000011 |
3 | 1002001021211221201022 |
4 | 22132301201000003 |
5 | 141021422334242 |
6 | 5100410100055 |
7 | 545606666366 |
oct | 123661410003 |
9 | 32037757638 |
10 | 11253714947 |
11 | 4855479672 |
12 | 2220a1a62b |
13 | 10a466ac37 |
14 | 78a8760dd |
15 | 45cea90d2 |
hex | 29ec61003 |
11253714947 has 4 divisors (see below), whose sum is σ = 11255227536. Its totient is φ = 11252202360.
The previous prime is 11253714937. The next prime is 11253715003. The reversal of 11253714947 is 74941735211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11253714947 - 24 = 11253714931 is a prime.
It is a super-2 number, since 2×112537149472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11253714898 and 11253714907.
It is not an unprimeable number, because it can be changed into a prime (11253714907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 745079 + ... + 760032.
It is an arithmetic number, because the mean of its divisors is an integer number (2813806884).
Almost surely, 211253714947 is an apocalyptic number.
11253714947 is a deficient number, since it is larger than the sum of its proper divisors (1512589).
11253714947 is an equidigital number, since it uses as much as digits as its factorization.
11253714947 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1512588.
The product of its digits is 211680, while the sum is 44.
The spelling of 11253714947 in words is "eleven billion, two hundred fifty-three million, seven hundred fourteen thousand, nine hundred forty-seven".
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