Base | Representation |
---|---|
bin | 10100111101110000… |
… | …00001110011001001 |
3 | 1002001102001200120011 |
4 | 22132320001303021 |
5 | 141022342002103 |
6 | 5100510431521 |
7 | 545630336563 |
oct | 123670016311 |
9 | 32042050504 |
10 | 11255422153 |
11 | 4856435288 |
12 | 22215025a1 |
13 | 10a4b18011 |
14 | 78ab9c333 |
15 | 45d1e4d6d |
hex | 29ee01cc9 |
11255422153 has 4 divisors (see below), whose sum is σ = 11446192080. Its totient is φ = 11064652228.
The previous prime is 11255422151. The next prime is 11255422181. The reversal of 11255422153 is 35122455211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35122455211 = 10973 ⋅3200807.
It is a cyclic number.
It is not a de Polignac number, because 11255422153 - 21 = 11255422151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11255422151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95384875 + ... + 95384992.
It is an arithmetic number, because the mean of its divisors is an integer number (2861548020).
Almost surely, 211255422153 is an apocalyptic number.
It is an amenable number.
11255422153 is a deficient number, since it is larger than the sum of its proper divisors (190769927).
11255422153 is an equidigital number, since it uses as much as digits as its factorization.
11255422153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190769926.
The product of its digits is 12000, while the sum is 31.
Adding to 11255422153 its reverse (35122455211), we get a palindrome (46377877364).
The spelling of 11255422153 in words is "eleven billion, two hundred fifty-five million, four hundred twenty-two thousand, one hundred fifty-three".
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