11280113 has 4 divisors (see below), whose sum is σ = 12147828. Its totient is φ = 10412400.

The previous prime is 11280077. The next prime is 11280133. The reversal of 11280113 is 31108211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31108211 = 1301 ⋅23911.

It can be written as a sum of positive squares in 2 ways, for example, as 5438224 + 5841889 = 2332^2 + 2417^2 .

It is a cyclic number.

It is not a de Polignac number, because 11280113 - 2²⁰ = 10231537 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11280091 and 11280100.

It is not an unprimeable number, because it can be changed into a prime (11280133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433838 + ... + 433863.

It is an arithmetic number, because the mean of its divisors is an integer number (3036957).

Almost surely, 2^11280113 is an apocalyptic number.

11280113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11280113 is a deficient number, since it is larger than the sum of its proper divisors (867715).

11280113 is an equidigital number, since it uses as much as digits as its factorization.

11280113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 867714.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 11280113 is about 3358.5879473374. The cubic root of 11280113 is about 224.2699829779.

Adding to 11280113 its reverse (31108211), we get a palindrome (42388324).

The spelling of 11280113 in words is "eleven million, two hundred eighty thousand, one hundred thirteen".