Base | Representation |
---|---|
bin | 110100100111101010… |
… | …0110110010111001011 |
3 | 101210200011110112201010 |
4 | 1221033110312113023 |
5 | 3322411000442212 |
6 | 123524514255003 |
7 | 11110150165524 |
oct | 1511724662713 |
9 | 353604415633 |
10 | 113000015307 |
11 | 43a17621003 |
12 | 19a97587463 |
13 | a86abb83aa |
14 | 567d7d184b |
15 | 2e1569103c |
hex | 1a4f5365cb |
113000015307 has 4 divisors (see below), whose sum is σ = 150666687080. Its totient is φ = 75333343536.
The previous prime is 113000015299. The next prime is 113000015309. The reversal of 113000015307 is 703510000311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 113000015307 - 23 = 113000015299 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113000015309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18833335882 + ... + 18833335887.
It is an arithmetic number, because the mean of its divisors is an integer number (37666671770).
Almost surely, 2113000015307 is an apocalyptic number.
113000015307 is a deficient number, since it is larger than the sum of its proper divisors (37666671773).
113000015307 is an equidigital number, since it uses as much as digits as its factorization.
113000015307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37666671772.
The product of its (nonzero) digits is 315, while the sum is 21.
Adding to 113000015307 its reverse (703510000311), we get a palindrome (816510015618).
The spelling of 113000015307 in words is "one hundred thirteen billion, fifteen thousand, three hundred seven".
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