113001100232131 has 4 divisors (see below), whose sum is σ = 113233135346032. Its totient is φ = 112769065118232.

The previous prime is 113001100232107. The next prime is 113001100232159. The reversal of 113001100232131 is 131232001100311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113001100232131 - 2⁵ = 113001100232099 is a prime.

It is a super-2 number, since 2×113001100232131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113001100232099 and 113001100232108.

It is not an unprimeable number, because it can be changed into a prime (113001100232161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116017556220 + ... + 116017557193.

It is an arithmetic number, because the mean of its divisors is an integer number (28308283836508).

Almost surely, 2^{113001100232131} is an apocalyptic number.

113001100232131 is a deficient number, since it is larger than the sum of its proper divisors (232035113901).

113001100232131 is an equidigital number, since it uses as much as digits as its factorization.

113001100232131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232035113900.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 113001100232131 its reverse (131232001100311), we get a palindrome (244233101332442).

The spelling of 113001100232131 in words is "one hundred thirteen trillion, one billion, one hundred million, two hundred thirty-two thousand, one hundred thirty-one".