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11300131300201 = 12970787120443
BaseRepresentation
bin1010010001110000010001…
…0011111110001101101001
31111000021121120122110001221
42210130010103332031221
52440120132103101301
640011113022542041
72244256534143262
oct244340423761551
944007546573057
1011300131300201
1136673a4585a77
12132605b137921
1363c7a0505193
142b0d01cd5969
15148e20651da1
hexa47044fe369

11300131300201 has 4 divisors (see below), whose sum is σ = 11300218550352. Its totient is φ = 11300044050052.

The previous prime is 11300131300193. The next prime is 11300131300207. The reversal of 11300131300201 is 10200313100311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11300131300201 - 23 = 11300131300193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11300131300207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43430515 + ... + 43689928.

It is an arithmetic number, because the mean of its divisors is an integer number (2825054637588).

Almost surely, 211300131300201 is an apocalyptic number.

It is an amenable number.

11300131300201 is a deficient number, since it is larger than the sum of its proper divisors (87250151).

11300131300201 is an equidigital number, since it uses as much as digits as its factorization.

11300131300201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87250150.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11300131300201 its reverse (10200313100311), we get a palindrome (21500444400512).

The spelling of 11300131300201 in words is "eleven trillion, three hundred billion, one hundred thirty-one million, three hundred thousand, two hundred one".

Divisors: 1 129707 87120443 11300131300201