Base | Representation |
---|---|
bin | 100001101011010… |
… | …1010110101110011 |
3 | 2220202022202200201 |
4 | 1003112222311303 |
5 | 4303241003430 |
6 | 304044100031 |
7 | 40000656424 |
oct | 10326526563 |
9 | 2822282621 |
10 | 1130016115 |
11 | 52a956918 |
12 | 276534617 |
13 | 1501600b7 |
14 | aa11364b |
15 | 693148ca |
hex | 435aad73 |
1130016115 has 4 divisors (see below), whose sum is σ = 1356019344. Its totient is φ = 904012888.
The previous prime is 1130016113. The next prime is 1130016143. The reversal of 1130016115 is 5116100311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1130016115 - 21 = 1130016113 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1130016092 and 1130016101.
It is not an unprimeable number, because it can be changed into a prime (1130016113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113001607 + ... + 113001616.
It is an arithmetic number, because the mean of its divisors is an integer number (339004836).
Almost surely, 21130016115 is an apocalyptic number.
1130016115 is a deficient number, since it is larger than the sum of its proper divisors (226003229).
1130016115 is an equidigital number, since it uses as much as digits as its factorization.
1130016115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226003228.
The product of its (nonzero) digits is 90, while the sum is 19.
The square root of 1130016115 is about 33615.7123232574. The cubic root of 1130016115 is about 1041.5853886307.
Adding to 1130016115 its reverse (5116100311), we get a palindrome (6246116426).
The spelling of 1130016115 in words is "one billion, one hundred thirty million, sixteen thousand, one hundred fifteen".
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