Search a number
-
+
1130021213003 = 17221093006551
BaseRepresentation
bin10000011100011010100…
…000110101001101001011
311000000210010021101212122
4100130122200311031023
5122003240412304003
62223042524201455
7144432656553614
oct20343240651513
94000703241778
101130021213003
113a626a573731
1216300999928b
1382739689937
143c99c674c0b
151e5db3ba238
hex1071a83534b

1130021213003 has 8 divisors (see below), whose sum is σ = 1196547564960. Its totient is φ = 1063500918400.

The previous prime is 1130021212981. The next prime is 1130021213011. The reversal of 1130021213003 is 3003121200311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130021213003 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is not an unprimeable number, because it can be changed into a prime (1130021213203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1127423 + ... + 1879128.

It is an arithmetic number, because the mean of its divisors is an integer number (149568445620).

Almost surely, 21130021213003 is an apocalyptic number.

1130021213003 is a deficient number, since it is larger than the sum of its proper divisors (66526351957).

1130021213003 is a wasteful number, since it uses less digits than its factorization.

1130021213003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3028677.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1130021213003 its reverse (3003121200311), we get a palindrome (4133142413314).

The spelling of 1130021213003 in words is "one trillion, one hundred thirty billion, twenty-one million, two hundred thirteen thousand, three".

Divisors: 1 17 22109 375853 3006551 51111367 66471836059 1130021213003