1130021301313 has 4 divisors (see below), whose sum is σ = 1133002888240. Its totient is φ = 1127039714388.

The previous prime is 1130021301293. The next prime is 1130021301319. The reversal of 1130021301313 is 3131031200311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130021301313 - 2⁵ = 1130021301281 is a prime.

It is a super-2 number, since 2×1130021301313² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130021301319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1490792895 + ... + 1490793652.

It is an arithmetic number, because the mean of its divisors is an integer number (283250722060).

Almost surely, 2^{1130021301313} is an apocalyptic number.

It is an amenable number.

1130021301313 is a deficient number, since it is larger than the sum of its proper divisors (2981586927).

1130021301313 is an equidigital number, since it uses as much as digits as its factorization.

1130021301313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2981586926.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1130021301313 its reverse (3131031200311), we get a palindrome (4261052501624).

The spelling of 1130021301313 in words is "one trillion, one hundred thirty billion, twenty-one million, three hundred one thousand, three hundred thirteen".