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11300300531 = 13869253887
BaseRepresentation
bin10101000011000110…
…01110011011110011
31002011112111202010022
422201203032123303
5141120334104111
65105152354055
7550013653412
oct124143163363
932145452108
1011300300531
1148797a8053
12223454592b
1310b11cc180
14792b21479
1546210c2db
hex2a18ce6f3

11300300531 has 4 divisors (see below), whose sum is σ = 12169554432. Its totient is φ = 10431046632.

The previous prime is 11300300491. The next prime is 11300300579. The reversal of 11300300531 is 13500300311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13500300311 = 55724237523.

It is a cyclic number.

It is not a de Polignac number, because 11300300531 - 230 = 10226558707 is a prime.

It is a super-2 number, since 2×113003005312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11300300581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434626931 + ... + 434626956.

It is an arithmetic number, because the mean of its divisors is an integer number (3042388608).

Almost surely, 211300300531 is an apocalyptic number.

11300300531 is a deficient number, since it is larger than the sum of its proper divisors (869253901).

11300300531 is an equidigital number, since it uses as much as digits as its factorization.

11300300531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 869253900.

The product of its (nonzero) digits is 135, while the sum is 17.

Adding to 11300300531 its reverse (13500300311), we get a palindrome (24800600842).

The spelling of 11300300531 in words is "eleven billion, three hundred million, three hundred thousand, five hundred thirty-one".

Divisors: 1 13 869253887 11300300531