Base | Representation |
---|---|
bin | 10000011100011011001… |
… | …001111111010010111001 |
3 | 11000000210212120112220202 |
4 | 100130123021333102321 |
5 | 122003301143032413 |
6 | 2223043551331545 |
7 | 144433150351241 |
oct | 20343311772271 |
9 | 4000725515822 |
10 | 1130032002233 |
11 | 3a6275672852 |
12 | 163011520bb5 |
13 | 8273b9967b4 |
14 | 3c99dc82b21 |
15 | 1e5dc2ebe58 |
hex | 1071b27f4b9 |
1130032002233 has 4 divisors (see below), whose sum is σ = 1130045531520. Its totient is φ = 1130018472948.
The previous prime is 1130032002199. The next prime is 1130032002271. The reversal of 1130032002233 is 3322002300311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1130032002233 - 28 = 1130032001977 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1130032002293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6638573 + ... + 6806666.
It is an arithmetic number, because the mean of its divisors is an integer number (282511382880).
Almost surely, 21130032002233 is an apocalyptic number.
It is an amenable number.
1130032002233 is a deficient number, since it is larger than the sum of its proper divisors (13529287).
1130032002233 is an equidigital number, since it uses as much as digits as its factorization.
1130032002233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13529286.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 1130032002233 its reverse (3322002300311), we get a palindrome (4452034302544).
The spelling of 1130032002233 in words is "one trillion, one hundred thirty billion, thirty-two million, two thousand, two hundred thirty-three".
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