Base | Representation |
---|---|
bin | 110100100111110000… |
… | …1100000001000100011 |
3 | 101210200101201001112110 |
4 | 1221033201200020203 |
5 | 3322412323112011 |
6 | 123525113330403 |
7 | 11110220321544 |
oct | 1511741401043 |
9 | 353611631473 |
10 | 113003332131 |
11 | 43a19486a88 |
12 | 19a98706a03 |
13 | a86b7aa001 |
14 | 56800164cb |
15 | 2e15ae8ba6 |
hex | 1a4f860223 |
113003332131 has 4 divisors (see below), whose sum is σ = 150671109512. Its totient is φ = 75335554752.
The previous prime is 113003332121. The next prime is 113003332139. The reversal of 113003332131 is 131233300311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 113003332131 - 215 = 113003299363 is a prime.
It is a super-2 number, since 2×1130033321312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113003332098 and 113003332107.
It is not an unprimeable number, because it can be changed into a prime (113003332139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18833888686 + ... + 18833888691.
It is an arithmetic number, because the mean of its divisors is an integer number (37667777378).
Almost surely, 2113003332131 is an apocalyptic number.
113003332131 is a deficient number, since it is larger than the sum of its proper divisors (37667777381).
113003332131 is an equidigital number, since it uses as much as digits as its factorization.
113003332131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37667777380.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 113003332131 its reverse (131233300311), we get a palindrome (244236632442).
The spelling of 113003332131 in words is "one hundred thirteen billion, three million, three hundred thirty-two thousand, one hundred thirty-one".
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