Base | Representation |
---|---|
bin | 10101000011000111… |
… | …01010001001011001 |
3 | 1002011112201111211101 |
4 | 22201203222021121 |
5 | 141120401222131 |
6 | 5105155031401 |
7 | 550014635350 |
oct | 124143521131 |
9 | 32145644741 |
10 | 11300414041 |
11 | 4879875364 |
12 | 223459b561 |
13 | 10b123ba37 |
14 | 792b50997 |
15 | 462130c61 |
hex | 2a18ea259 |
11300414041 has 4 divisors (see below), whose sum is σ = 12914758912. Its totient is φ = 9686069172.
The previous prime is 11300414033. The next prime is 11300414051. The reversal of 11300414041 is 14041400311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14041400311 = 19 ⋅739021069.
It is a cyclic number.
It is not a de Polignac number, because 11300414041 - 23 = 11300414033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11300414011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 807172425 + ... + 807172438.
It is an arithmetic number, because the mean of its divisors is an integer number (3228689728).
Almost surely, 211300414041 is an apocalyptic number.
It is an amenable number.
11300414041 is a deficient number, since it is larger than the sum of its proper divisors (1614344871).
11300414041 is an equidigital number, since it uses as much as digits as its factorization.
11300414041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1614344870.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11300414041 its reverse (14041400311), we get a palindrome (25341814352).
The spelling of 11300414041 in words is "eleven billion, three hundred million, four hundred fourteen thousand, forty-one".
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