Base | Representation |
---|---|
bin | 1010010001110001011010… |
… | …1110010111111111101011 |
3 | 1111000022102002220202121202 |
4 | 2210130112232113333223 |
5 | 2440121300143231220 |
6 | 40011203415554415 |
7 | 2244300304636154 |
oct | 244342656277753 |
9 | 44008362822552 |
10 | 11300440211435 |
11 | 3667542996611 |
12 | 132612668ba0b |
13 | 63c81c5030ab |
14 | 2b0d30d4892b |
15 | 148e3c821275 |
hex | a4716b97feb |
11300440211435 has 8 divisors (see below), whose sum is σ = 13563482001216. Its totient is φ = 9038383004160.
The previous prime is 11300440211353. The next prime is 11300440211443. The reversal of 11300440211435 is 53411204400311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11300440211435 - 224 = 11300423434219 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11300440211398 and 11300440211407.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246120374 + ... + 246166283.
It is an arithmetic number, because the mean of its divisors is an integer number (1695435250152).
Almost surely, 211300440211435 is an apocalyptic number.
11300440211435 is a deficient number, since it is larger than the sum of its proper divisors (2263041789781).
11300440211435 is an equidigital number, since it uses as much as digits as its factorization.
11300440211435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 492291253.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 11300440211435 its reverse (53411204400311), we get a palindrome (64711644611746).
The spelling of 11300440211435 in words is "eleven trillion, three hundred billion, four hundred forty million, two hundred eleven thousand, four hundred thirty-five".
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